1 MAT116 Final Review Session Chapter 3: Polynomial and Rational Functions
2 Quadratic Function A quadratic function is defined by a quadratic or second-degree polynomial. Standard Form π π₯ =π π₯ 2 +ππ₯+π, where a β 0. Vertex Form π π₯ =π (π₯ββ) 2 +π, where a β 0.
3 Vertex and Axis of SymmetryThe point (h,k) is the vertex of the parabola if it is in vertex form. The point (β π 2π ,π β π 2π ) is the vertex of the parabola if it is in standard form. The vertical line x = β π 2π is called the axis of symmetry for the graph of π π₯ =π π₯ 2 +ππ₯+π.
4 Examples: Find the Following1. π π₯ =2(π₯β3 ) 2 +5 Vertex: 2. π π₯ =3 π₯ 2 β5π₯+2 Axis of Symmetry:
5 Opening and Maximum and MinimumIf a > 0, the graph of a quadratic function opens upward If a < 0, the graph opens downward If a > 0, k is the minimum value of the function If a < 0, k is the maximum value of the function Examples: Find the min or max and state if it opens up or down. 3. β π₯ =β2 π₯ 2 +4π₯+7
6 Examples: Find the x and y intercepts.The y-intercept is found by letting x = 0 and solving for y. Write as an ordered pair: ( 0 , y ) The x-intercepts are found by letting y = 0 and solving for x. Solve by factoring, square roots, or the quadratic formula. Write as an ordered pair: ( x , 0 ) Examples: Find the x and y intercepts. 4. β π₯ =β2 π₯ 2 +4π₯+7 5. π π₯ =2(π₯β3 ) 2 +5
7 Examples: Identify the following.6. π¦=2 π₯ 2 +8π₯+6 Vertex: Axis of Symmetry: Minimum: Maximum: Y-intercept: X-intercepts: Vertex form:
8 Quadratic InequalitiesStrategy: Solving a Quadratic Inequality by the Graphical Method Get 0 on one side of the inequality and a quadratic polynomial on the other side. Find all roots to the quadratic polynomial. Graph the corresponding quadratic function. The roots found in step (2) determine the x-intercepts. Read the solution set to the inequality from the graph of the parabola.
9 Examples: Solve the inequality and graph itExamples: Solve the inequality and graph it. Write your answer in interval notation. 7. π₯ 2 +6π₯>β8 8. 2π₯+15< π₯ 2
10 Zeroes of Polynomial FunctionsDivision of Polynomials Long Division β can be used to divide any two polynomials Synthetic Division - Can only be used to divide two polynomials when dividing by x-k. Remainder Theorem If R is the remainder when a polynomial P(x) is divided by x β c, then R = P(c).
11 Examples: Solve. 9. ( π₯ 3 +5 π₯ 2 β3π₯+15)Γ·( π₯ 2 β2) 10. π₯ 2 +5π₯+6 π₯+29. ( π₯ 3 +5 π₯ 2 β3π₯+15)Γ·( π₯ 2 β2) 10. π₯ 2 +5π₯+6 π₯+2 11. If β π₯ =β3 π₯ 3 +5 π₯ 2 β6π₯+1, use the Remainder Theorem to find β(β1).
12 Rational Zero Theorem If π π₯ = π π π₯ π + π πβ1 π₯ πβ1 +β¦+ π 1 π₯+ π 0π π₯ = π π π₯ π + π πβ1 π₯ πβ1 +β¦+ π 1 π₯+ π 0 is a polynomial function with integral coefficients (an β 0 and a0 β 0) and π π (in lowest terms) is a rational zero of π(π₯), then p is a factor of the constant term a0 and q is a factor of the leading coefficient an . To find the rational zeros, divided all the factors of the constant term by all the factors of the lead coefficient.
13 Examples: List all possible rational roots and find all the real and imaginary zeroes.12. β π₯ = π₯ 3 β π₯ 2 β7π₯+15 h(x)=x3-x2-7x+15
14 Theory of Equations Multiplicity: If the factor x β c occurs k times in the complete factorization of the polynomial P(x), then c is called a root of P(x) = 0 with multiplicity k. Multiplicity is the number of times a zero occurs. Conjugate Pairs Theorem: If P(x) = 0 is a polynomial equation with real coefficients and the complex number a + bi (b β 0) is a root, then a β bi is also a root
15 Examples: State the degree, find all real and imaginary roots and state their multiplicities.13. π π₯ = π₯ 5 β6 π₯ 4 +9 π₯ 3 f(x)=x5-6x4+9x3
16 Examples: Find a polynomial with the given roots.
17 Symmetry Symmetric about the y-axis: f(x) is an even function if f(-x) = f(x) Symmetric about the origin: f(x) is an odd function if f(-x) = -f(x) A quadratic function is symmetric about the axis of symmetry if x = β π 2π
18 Examples: State whether the function is even, odd or neither.16. π π₯ = π₯ 6 β π₯ 4 + π₯ 2 β8 17. π π₯ =4 π₯ 3 βπ₯ 18. β π₯ = π₯ 3 β π₯ 2 +2
19 Behavior Multiplicity of ZeroesEven Multiplicity: the graph touches but does NOT cross the x-axis at the x-intercept Odd Multiplicity: the graph crosses the x-axis at the x-intercept The Leading Coefficient Test helps to determine the end behavior of a graph.
20 Examples: Graph the following.19. π π₯ = π₯ 3 β3 π₯ β π₯ = π₯ 6 +2 π₯ 5 + π₯ 4
21 Polynomial InequalitiesVery similar to solving Quadratic Inequalities. Strategy: Solving a Polynomial Inequality by the Graphical Method Get 0 on one side of the inequality and a polynomial on the other side. Find all roots to the polynomial. Graph the corresponding function. The roots found in step (2) determine the x-intercepts.
22 Examples: Solve and write your answer in interval notation.21. π₯ 3 +4 π₯ 2 βπ₯β4>0 22. π₯ 3 +2 π₯ 2 β2π₯β4<0
23 Rational Functions If P(x) and Q(x) are polynomials, then a function of the form π π₯ = π(π₯) π(π₯) is called a rational function, provided that Q(x) is not the zero polynomial.
24 Asymptotes An asymptote is an βinvisibleβ line that the function is always approaching but never reaching. Vertical asymptotes correspond to where Q(x)= 0. Horizontal Asymptotes If the numerator has a lower degree than the denominator, the horizontal asymptote is the line y=0. If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is the line y=a/b where a is the lead coefficient of the numerator and b is the lead coefficient of the denominator. Oblique (Slant) Asymptote If the degree of the numerator is one degree higher than the degree of the denominator, the graph of the function has an oblique asymptote. Divide the numerator by the denominator, the quotient (without the remainder) is your oblique asymptote.
25 Examples: Find the asymptotes.23. π π₯ = β2π₯ π₯ 2 +6π₯+9 24. π π₯ = 2π₯ 2 β11 π₯ 2 β9 25. π π₯ = π₯ 2 β6π₯+7 π₯+5
26 Examples: Solve the Rational Inequality.26. π₯β1 π₯β3 >0 27. π₯+3 π₯β2 <0
27 Miscellaneous EquationsEquations involving absolute value can include more than one absolute value or contain higher degree polynomials where the definition for absolute value is used to determine the solutions. Equations involving square roots are solved by squaring both sides once a radical is isolated on one side of the equation. Equations with rational exponents are solved by raising both sides of the equation to a reciprocal power and considering positive and negative possibilities for even roots. Equations of quadratic type can be solved by substituting a single variable for a more complicated expression. Factoring is often the fastest method for solving an equation.
28 Examples: Solve. Absolute Value Examples: 28. π£ 2 β3π£ =5π£ 28. π£ 2 β3π£ =5π£ 29. π₯+5 = 2π₯+1 30. π₯β4 β1=β4π₯
29 Examples: Solve. Square Root Examples: 31. π₯+1 =π₯β5 32. 1 π§ = 3 4π§+131. π₯+1 =π₯β5 π§ = 3 4π§+1 33. π₯+40 β π₯ =4
30 Examples: Solve Rational Exponent Examples: 34. π₯ 2 3 =2 34. π₯ =2 35. π€ β 3 2 =27 36. (π‘β1) β 1 2 = 1 2
31 Examples: Solve. Quadratic Type Examples: 37. π₯ 4 + 6π₯ 2 β7=037. π₯ 4 + 6π₯ 2 β7=0 38. π₯ 4 β π₯ 2 β12=0 39. π₯β 7π₯ =0
32 Examples: Solve. Solving Higher Degree Polynomials with Factoring:40. 2+π₯β2 π₯ 2 = π₯ 3 41. 2 π₯ π₯ 2 βπ₯β500=0 42. π₯ 4 β81=0
33 Chapter 3 Review Quadratic Function Theory of EquationsRational Functions Miscellaneous Equations
34 Example Solutions vertex = (3,5) Vertex = ( 5 6 ,β 1 12 ) AoS = x= 5 6Max = 5, opens down Y-int. = (0,7), x-int. = ( 2Β± ,0) Y-int. = (0,23), x-int.= ( 6Β±i ,0) Vertex = (-2,2), AoS = x = -2, min = -2, y-int. = (0,16), x-int. = (-3,0), (-1,0), Vertex Form = 2(x+2 ) 2 β2 ββ,β4 U(β2,β) ββ,β3 U(5,β) x+5 R: -x+25 x+3 R: 0 h(-1)=15 p q =Β± 1,3,5,15 1 , x = {-3, 2Β±i} degree: 5, x = 0 mult. 3, x = 3 mult. 2 x 3 β12 x 2 +64xβ768 x 3 β13 x 2 +65xβ125 Even Odd Neither Graph β4, β1 U 1,β ββ, β2 U β 2 , 2 x = 3, y = 0 x = 3, x = -3, y = 2 X = -5, y = x-11 ββ, 1 U 3, β (-3,2) v = 0,8,-2 x = 2, 4 x = -1, 1 x = 8,3 z = 2Β± x = 9 x = 2 2 w = 1/9 t = 5 x= Β±1, Β±i 7 x = Β±2, Β±i 3 x = 16, 9 x = 1, -1, -2 x = β500, Β± 1 2 x = -3, 3